RE: Multiple clauses in KW:FINDALL

Sigh. I found the trouble. It seems I must package-qualify the TEST
operator, like this:

(kw:findall '?x '(and (hobbit ?x age ?a) (kw:test (< ?a 50))))

The only reason I stumbled upon this solution is because I happened to run a
test within the KW-USER package and it worked.

Ah well...

dey

-----Original Message-----
From: Jason Trenouth [mailto:jason.trenouth@globalgraphics.com]
Sent: Wednesday, September 29, 2004 5:13 AM
To: Young, David
Cc: 'lisp-hug@xanalys.com'
Subject: Re: Multiple clauses in KW:FINDALL


Young, David wrote:

>Hi. I would like to query our kb using something similar to the following.
>Assume I have to kw instances of class FRODO, one with age = 30, the other
>with age = 60. I then evaluate:
>
>(kw:findall '?x '(and (frodo ?x age ?age) ((< ?age 50))))
>
>However, I clearly don't understand somthing about FINDALL, as the above
>query returns *both* instances rather than just one. What am I doing wrong?
>
>  
>
I think the (( ... )) syntax just means: run the Lisp code. The result 
is not used to control the Prolog backtracking. If you want the result 
to control the backtracking then I think you have to use (test ( ... )). ie
 

	(kw:findall '?x '(and (frodo ?x age ?age) (test (< ?age 50))))

__Jason


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